What are the solutions to the equation x^2+22x=8x-53 ?

The solutions to the equation x^2+22x=8x-53 are x=-7+2i,x=-7-2i

Find the zeros of x^2+22x=8x-53

The zeros of x^2+22x=8x-53 are x=-7+2i,x=-7-2i

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x^{2} + 22 x = 8 x - 53

x = - 7 + 2 i, x = - 7 - 2 i

Solution steps

x^{2} + 22 x = 8 x - 53

Move

53

to the left side

x^{2} + 22 x + 53 = 8 x

Move

8 x

to the left side

x^{2} + 14 x + 53 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 53}{2 \cdot 1}

Simplify

1 4^{2} - 4 \cdot 1 \cdot 53 : 4 i

x_{1, 2} = \frac{- 14 \pm 4 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 4 i}{2 \cdot 1}, x_{2} = \frac{- 14 - 4 i}{2 \cdot 1}

x = \frac{- 14 + 4 i}{2 \cdot 1} : - 7 + 2 i

x = \frac{- 14 - 4 i}{2 \cdot 1} : - 7 - 2 i

The solutions to the quadratic equation are:

x = - 7 + 2 i, x = - 7 - 2 i

\frac{x ( x + 1 )}{2} = 120

x^{2} - 37 x + 27 = 0

7 x^{2} - 66 x + 27 = 0

x^{2} + (x + 5)^{2} = 5 + 16 (3 - x)

x^{2} + 4 = 13

What are the solutions to the equation x^2+22x=8x-53 ?
The solutions to the equation x^2+22x=8x-53 are x=-7+2i,x=-7-2i
Find the zeros of x^2+22x=8x-53
The zeros of x^2+22x=8x-53 are x=-7+2i,x=-7-2i