What are the solutions to the equation 7x^2-66x+27=0 ?

The solutions to the equation 7x^2-66x+27=0 are x=9,x= 3/7

Find the zeros of 7x^2-66x+27=0

The zeros of 7x^2-66x+27=0 are x=9,x= 3/7

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7 x^{2} - 66 x + 27 = 0

x = 9, x = \frac{3}{7}

Decimal Notation

x = 9, x = 0.42857 \dots

Solution steps

7 x^{2} - 66 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 66 ) \pm ( - 66 ) ^{2} - 4 \cdot 7 \cdot 27}{2 \cdot 7}

(- 66)^{2} - 4 \cdot 7 \cdot 27 = 60

x_{1, 2} = \frac{- ( - 66 ) \pm 60}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 66 ) + 60}{2 \cdot 7}, x_{2} = \frac{- ( - 66 ) - 60}{2 \cdot 7}

x = \frac{- ( - 66 ) + 60}{2 \cdot 7} : 9

x = \frac{- ( - 66 ) - 60}{2 \cdot 7} : \frac{3}{7}

The solutions to the quadratic equation are:

x = 9, x = \frac{3}{7}

x^{2} + (x + 5)^{2} = 5 + 16 (3 - x)

x^{2} + 4 = 13

x, 4 x^{2} + 12 x + 3 = 0

2 x^{2} = 7 x + 15

9 = π + r^{2} 16

What are the solutions to the equation 7x^2-66x+27=0 ?
The solutions to the equation 7x^2-66x+27=0 are x=9,x= 3/7
Find the zeros of 7x^2-66x+27=0
The zeros of 7x^2-66x+27=0 are x=9,x= 3/7