What are the solutions to the equation 9=pi+r^216 ?

The solutions to the equation 9=pi+r^216 are r=(sqrt(9-pi))/4 ,r=-(sqrt(9-pi))/4

Find the zeros of 9=pi+r^216

The zeros of 9=pi+r^216 are r=(sqrt(9-pi))/4 ,r=-(sqrt(9-pi))/4

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9 = π + r^{2} 16

r = \frac{9 - π}{4}, r = - \frac{9 - π}{4}

Decimal Notation

r = 0.60510 \dots, r = - 0.60510 \dots

Solution steps

9 = π + r^{2} \cdot 16

Switch sides

π + r^{2} \cdot 16 = 9

Move

π

to the right side

r^{2} \cdot 16 = 9 - π

Divide both sides by

16

r^{2} = \frac{9 - π}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{9 - π}{16}, r = - \frac{9 - π}{16}

\frac{9 - π}{16} = \frac{9 - π}{4}

- \frac{9 - π}{16} = - \frac{9 - π}{4}

r = \frac{9 - π}{4}, r = - \frac{9 - π}{4}

2 x^{2} = x + 8

(x + 4)^{2} = 31

(5 p + 2)^{2} = 8

c^{2} - 7 c + 12 = 0

t^{2} - 3 t - 7 = 0

What are the solutions to the equation 9=pi+r^216 ?
The solutions to the equation 9=pi+r^216 are r=(sqrt(9-pi))/4 ,r=-(sqrt(9-pi))/4
Find the zeros of 9=pi+r^216
The zeros of 9=pi+r^216 are r=(sqrt(9-pi))/4 ,r=-(sqrt(9-pi))/4