What are the solutions to the equation (x+4)^2=31 ?

The solutions to the equation (x+4)^2=31 are x=sqrt(31)-4,x=-sqrt(31)-4

Find the zeros of (x+4)^2=31

The zeros of (x+4)^2=31 are x=sqrt(31)-4,x=-sqrt(31)-4

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(x + 4)^{2} = 31

x = 31 - 4, x = - 31 - 4

Decimal Notation

x = 1.56776 \dots, x = - 9.56776 \dots

Solution steps

(x + 4)^{2} = 31

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = 31 : x = 31 - 4

Solve

x + 4 = - 31 : x = - 31 - 4

The solutions to the quadratic equation are:

x = 31 - 4, x = - 31 - 4

(5 p + 2)^{2} = 8

c^{2} - 7 c + 12 = 0

t^{2} - 3 t - 7 = 0

3 x - x^{2} = 7

8 + 2 x^{2} = 0

What are the solutions to the equation (x+4)^2=31 ?
The solutions to the equation (x+4)^2=31 are x=sqrt(31)-4,x=-sqrt(31)-4
Find the zeros of (x+4)^2=31
The zeros of (x+4)^2=31 are x=sqrt(31)-4,x=-sqrt(31)-4