What are the solutions to the equation 3x-x^2=7 ?

The solutions to the equation 3x-x^2=7 are x= 3/2-i(sqrt(19))/2 ,x= 3/2+i(sqrt(19))/2

Find the zeros of 3x-x^2=7

The zeros of 3x-x^2=7 are x= 3/2-i(sqrt(19))/2 ,x= 3/2+i(sqrt(19))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x - x^{2} = 7

x = \frac{3}{2} - i \frac{19}{2}, x = \frac{3}{2} + i \frac{19}{2}

Solution steps

3 x - x^{2} = 7

Move

7

to the left side

3 x - x^{2} - 7 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 3 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) ( - 7 )}{2 ( - 1 )}

Simplify

3^{2} - 4 (- 1) (- 7) : 19 i

x_{1, 2} = \frac{- 3 \pm 19 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 19 i}{2 ( - 1 )}, x_{2} = \frac{- 3 - 19 i}{2 ( - 1 )}

x = \frac{- 3 + 19 i}{2 ( - 1 )} : \frac{3}{2} - i \frac{19}{2}

x = \frac{- 3 - 19 i}{2 ( - 1 )} : \frac{3}{2} + i \frac{19}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} - i \frac{19}{2}, x = \frac{3}{2} + i \frac{19}{2}

8 + 2 x^{2} = 0

x^{2} - 300 x + 12500 = 0

x^{2} - x = 8

t^{2} + 2 t - 19 = 5

2 x^{2} - 4 x + 15

What are the solutions to the equation 3x-x^2=7 ?
The solutions to the equation 3x-x^2=7 are x= 3/2-i(sqrt(19))/2 ,x= 3/2+i(sqrt(19))/2
Find the zeros of 3x-x^2=7
The zeros of 3x-x^2=7 are x= 3/2-i(sqrt(19))/2 ,x= 3/2+i(sqrt(19))/2