What are the solutions to the equation 20x^2-5x=0 ?

The solutions to the equation 20x^2-5x=0 are x= 1/4 ,x=0

Find the zeros of 20x^2-5x=0

The zeros of 20x^2-5x=0 are x= 1/4 ,x=0

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20 x^{2} - 5 x = 0

x = \frac{1}{4}, x = 0

Decimal Notation

x = 0.25, x = 0

Solution steps

20 x^{2} - 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 20 \cdot 0}{2 \cdot 20}

(- 5)^{2} - 4 \cdot 20 \cdot 0 = 5

x_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 20}, x_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 20}

x = \frac{- ( - 5 ) + 5}{2 \cdot 20} : \frac{1}{4}

x = \frac{- ( - 5 ) - 5}{2 \cdot 20} : 0

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = 0

3 x - 4 x^{2} = - 5

2 x (x - 3) + 7 = 0

2 x^{2} + 4 x + 16 = 0

3 d^{2} + 8 d = 40

2 a - a^{2} = 3

What are the solutions to the equation 20x^2-5x=0 ?
The solutions to the equation 20x^2-5x=0 are x= 1/4 ,x=0
Find the zeros of 20x^2-5x=0
The zeros of 20x^2-5x=0 are x= 1/4 ,x=0