What are the solutions to the equation (m+3)(m-4)=-6 ?

The solutions to the equation (m+3)(m-4)=-6 are m=3,m=-2

Find the zeros of (m+3)(m-4)=-6

The zeros of (m+3)(m-4)=-6 are m=3,m=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(m + 3) (m - 4) = - 6

m = 3, m = - 2

Solution steps

(m + 3) (m - 4) = - 6

Expand

(m + 3) (m - 4) : m^{2} - m - 12

m^{2} - m - 12 = - 6

Move

6

to the left side

m^{2} - m - 6 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

m_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, m_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

m = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

m = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

m = 3, m = - 2

2 (x - 8)^{2} + 3 = 13

8 x^{2} = 2 x + 1

6 x^{2} - 10 x = 19

3 x^{2} - 105 x + 750 = 0

x, f (x + h) = 3 x^{2} + 2 x - 4

What are the solutions to the equation (m+3)(m-4)=-6 ?
The solutions to the equation (m+3)(m-4)=-6 are m=3,m=-2
Find the zeros of (m+3)(m-4)=-6
The zeros of (m+3)(m-4)=-6 are m=3,m=-2