What are the solutions to the equation 6x^2-10x=19 ?

The solutions to the equation 6x^2-10x=19 are x=(5+sqrt(139))/6 ,x=(5-sqrt(139))/6

Find the zeros of 6x^2-10x=19

The zeros of 6x^2-10x=19 are x=(5+sqrt(139))/6 ,x=(5-sqrt(139))/6

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6 x^{2} - 10 x = 19

x = \frac{5 + 139}{6}, x = \frac{5 - 139}{6}

Decimal Notation

x = 2.79830 \dots, x = - 1.13163 \dots

Solution steps

6 x^{2} - 10 x = 19

Move

19

to the left side

6 x^{2} - 10 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 6 ( - 19 )}{2 \cdot 6}

(- 10)^{2} - 4 \cdot 6 (- 19) = 2139

x_{1, 2} = \frac{- ( - 10 ) \pm 2 139}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 139}{2 \cdot 6}, x_{2} = \frac{- ( - 10 ) - 2 139}{2 \cdot 6}

x = \frac{- ( - 10 ) + 2 139}{2 \cdot 6} : \frac{5 + 139}{6}

x = \frac{- ( - 10 ) - 2 139}{2 \cdot 6} : \frac{5 - 139}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 139}{6}, x = \frac{5 - 139}{6}

3 x^{2} - 105 x + 750 = 0

x, f (x + h) = 3 x^{2} + 2 x - 4

\frac{1}{4} x^{2} + 36 x = 0

15 x^{2} = 12

- 80 = x (x - 16)

What are the solutions to the equation 6x^2-10x=19 ?
The solutions to the equation 6x^2-10x=19 are x=(5+sqrt(139))/6 ,x=(5-sqrt(139))/6
Find the zeros of 6x^2-10x=19
The zeros of 6x^2-10x=19 are x=(5+sqrt(139))/6 ,x=(5-sqrt(139))/6