What are the solutions to the equation -7x^2-8x+24=0 ?

The solutions to the equation -7x^2-8x+24=0 are x=-(2(2+sqrt(46)))/7 ,x=(2(sqrt(46)-2))/7

Find the zeros of -7x^2-8x+24=0

The zeros of -7x^2-8x+24=0 are x=-(2(2+sqrt(46)))/7 ,x=(2(sqrt(46)-2))/7

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- 7 x^{2} - 8 x + 24 = 0

x = - \frac{2 ( 2 + 46 )}{7}, x = \frac{2 ( 46 - 2 )}{7}

Decimal Notation

x = - 2.50923 \dots, x = 1.36637 \dots

Solution steps

- 7 x^{2} - 8 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 7 ) \cdot 24}{2 ( - 7 )}

(- 8)^{2} - 4 (- 7) \cdot 24 = 446

x_{1, 2} = \frac{- ( - 8 ) \pm 4 46}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 46}{2 ( - 7 )}, x_{2} = \frac{- ( - 8 ) - 4 46}{2 ( - 7 )}

x = \frac{- ( - 8 ) + 4 46}{2 ( - 7 )} : - \frac{2 ( 2 + 46 )}{7}

x = \frac{- ( - 8 ) - 4 46}{2 ( - 7 )} : \frac{2 ( 46 - 2 )}{7}

The solutions to the quadratic equation are:

x = - \frac{2 ( 2 + 46 )}{7}, x = \frac{2 ( 46 - 2 )}{7}

6 x^{2} + 3 x - 7 = 0

2 x^{2} + 9 x = 10

(2 x + 1)^{2} = 121

0 = 2 x^{2} - 4

3 x^{2} + 25 - 7 x = 2 x^{2} + 15

What are the solutions to the equation -7x^2-8x+24=0 ?
The solutions to the equation -7x^2-8x+24=0 are x=-(2(2+sqrt(46)))/7 ,x=(2(sqrt(46)-2))/7
Find the zeros of -7x^2-8x+24=0
The zeros of -7x^2-8x+24=0 are x=-(2(2+sqrt(46)))/7 ,x=(2(sqrt(46)-2))/7