What are the solutions to the equation k^2-7k-8=0 ?

The solutions to the equation k^2-7k-8=0 are k=8,k=-1

Find the zeros of k^2-7k-8=0

The zeros of k^2-7k-8=0 are k=8,k=-1

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k^{2} - 7 k - 8 = 0

k = 8, k = - 1

Solution steps

k^{2} - 7 k - 8 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 8) = 9

k_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 1}, k_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 1}

k = \frac{- ( - 7 ) + 9}{2 \cdot 1} : 8

k = \frac{- ( - 7 ) - 9}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

k = 8, k = - 1

d^{2} = (+ 4 - 1)^{2} + (+ 16 - 1)^{2}

11 m^{2} + 14 = 47

6 x^{2} = - 3 x

5 x^{2} - 7 = 3 x

z, 6 z^{2} + A z + B = 0

What are the solutions to the equation k^2-7k-8=0 ?
The solutions to the equation k^2-7k-8=0 are k=8,k=-1
Find the zeros of k^2-7k-8=0
The zeros of k^2-7k-8=0 are k=8,k=-1