What are the solutions to the equation quadraticformula x^2+5x+2=-4 ?

The solutions to the equation quadraticformula x^2+5x+2=-4 are x=-2,x=-3

Find the zeros of quadraticformula x^2+5x+2=-4

The zeros of quadraticformula x^2+5x+2=-4 are x=-2,x=-3

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x^{2} + 5 x + 2 = - 4

x = - 2, x = - 3

Solution steps

x^{2} + 5 x + 2 = - 4

Move

4

to the left side

x^{2} + 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- 5 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 1}{2 \cdot 1}, x_{2} = \frac{- 5 - 1}{2 \cdot 1}

x = \frac{- 5 + 1}{2 \cdot 1} : - 2

x = \frac{- 5 - 1}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = - 2, x = - 3

\frac{( x - 2 ) ^{2}}{2} = x + 2

x^{2} - 2 x + 4 = 0

4 a^{2} + 6 = 106

0 = 8 - 9 x^{2} + 13 x

x, x^{2} - x y + 2 y = 1

What are the solutions to the equation quadraticformula x^2+5x+2=-4 ?
The solutions to the equation quadraticformula x^2+5x+2=-4 are x=-2,x=-3
Find the zeros of quadraticformula x^2+5x+2=-4
The zeros of quadraticformula x^2+5x+2=-4 are x=-2,x=-3