What are the solutions to the equation -x^2+3x=-4 ?

The solutions to the equation -x^2+3x=-4 are x=-1,x=4

Find the zeros of -x^2+3x=-4

The zeros of -x^2+3x=-4 are x=-1,x=4

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- x^{2} + 3 x = - 4

x = - 1, x = 4

Solution steps

- x^{2} + 3 x = - 4

Move

4

to the left side

- x^{2} + 3 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 4}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 4 = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 ( - 1 )}, x_{2} = \frac{- 3 - 5}{2 ( - 1 )}

x = \frac{- 3 + 5}{2 ( - 1 )} : - 1

x = \frac{- 3 - 5}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = - 1, x = 4

2 x^{2} + 7 x 3 + 9 = 0

8 x^{2} = 7 - 10 x

2 x^{2} = \frac{1}{2}

y, 2 x^{3} + 3 y^{2} = 3 x + 7

5 8^{2} = x^{2} + x^{2}

What are the solutions to the equation -x^2+3x=-4 ?
The solutions to the equation -x^2+3x=-4 are x=-1,x=4
Find the zeros of -x^2+3x=-4
The zeros of -x^2+3x=-4 are x=-1,x=4