What are the solutions to the equation x^2-14x+60=11 ?

The solutions to the equation x^2-14x+60=11 are x=7

Find the zeros of x^2-14x+60=11

The zeros of x^2-14x+60=11 are x=7

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x^{2} - 14 x + 60 = 11

x = 7

Solution steps

x^{2} - 14 x + 60 = 11

Move

11

to the left side

x^{2} - 14 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 49 = 0

x_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 14 )}{2 \cdot 1}

\frac{- ( - 14 )}{2 \cdot 1} = 7

x = 7

The solution to the quadratic equation is:

x = 7

x^{2} - 3 x + 2 = 3

0 = 6 (x + 7)^{2} - 58

3 x^{2} - 18 x + 13

x^{2} - 42 x + 441 = 0

6 t^{2} - 13 t - 12 = - 7

What are the solutions to the equation x^2-14x+60=11 ?
The solutions to the equation x^2-14x+60=11 are x=7
Find the zeros of x^2-14x+60=11
The zeros of x^2-14x+60=11 are x=7