What are the solutions to the equation 6t^2-13t-12=-7 ?

The solutions to the equation 6t^2-13t-12=-7 are t= 5/2 ,t=-1/3

Find the zeros of 6t^2-13t-12=-7

The zeros of 6t^2-13t-12=-7 are t= 5/2 ,t=-1/3

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6 t^{2} - 13 t - 12 = - 7

t = \frac{5}{2}, t = - \frac{1}{3}

Decimal Notation

t = 2.5, t = - 0.33333 \dots

Solution steps

6 t^{2} - 13 t - 12 = - 7

Move

7

to the left side

6 t^{2} - 13 t - 5 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

(- 13)^{2} - 4 \cdot 6 (- 5) = 17

t_{1, 2} = \frac{- ( - 13 ) \pm 17}{2 \cdot 6}

Separate the solutions

t_{1} = \frac{- ( - 13 ) + 17}{2 \cdot 6}, t_{2} = \frac{- ( - 13 ) - 17}{2 \cdot 6}

t = \frac{- ( - 13 ) + 17}{2 \cdot 6} : \frac{5}{2}

t = \frac{- ( - 13 ) - 17}{2 \cdot 6} : - \frac{1}{3}

The solutions to the quadratic equation are:

t = \frac{5}{2}, t = - \frac{1}{3}

(2 x + 6)^{2} - 8 = 24

n^{2} - 4 = 77

(3 x + 8)^{2} = 12

3 y^{2} = 1 - y

11 y + 2 y^{2} = 21

What are the solutions to the equation 6t^2-13t-12=-7 ?
The solutions to the equation 6t^2-13t-12=-7 are t= 5/2 ,t=-1/3
Find the zeros of 6t^2-13t-12=-7
The zeros of 6t^2-13t-12=-7 are t= 5/2 ,t=-1/3