What are the solutions to the equation 11y+2y^2=21 ?

The solutions to the equation 11y+2y^2=21 are y= 3/2 ,y=-7

Find the zeros of 11y+2y^2=21

The zeros of 11y+2y^2=21 are y= 3/2 ,y=-7

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11 y + 2 y^{2} = 21

y = \frac{3}{2}, y = - 7

Decimal Notation

y = 1.5, y = - 7

Solution steps

11 y + 2 y^{2} = 21

Move

21

to the left side

11 y + 2 y^{2} - 21 = 0

Write in the standard form

a x^{2} + b x + c = 0

2 y^{2} + 11 y - 21 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 ( - 21 )}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 (- 21) = 17

y_{1, 2} = \frac{- 11 \pm 17}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- 11 + 17}{2 \cdot 2}, y_{2} = \frac{- 11 - 17}{2 \cdot 2}

y = \frac{- 11 + 17}{2 \cdot 2} : \frac{3}{2}

y = \frac{- 11 - 17}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

y = \frac{3}{2}, y = - 7

x, f (a + 1) = 5 x^{2} - x + 4

0 = (x - 5)^{2}

r^{2} + 18 r + 81 = 4

- 4 x^{2} + x = - 3

x^{2} - 12 x = - 6

What are the solutions to the equation 11y+2y^2=21 ?
The solutions to the equation 11y+2y^2=21 are y= 3/2 ,y=-7
Find the zeros of 11y+2y^2=21
The zeros of 11y+2y^2=21 are y= 3/2 ,y=-7