What are the solutions to the equation 5a^2+a-2=0 ?

The solutions to the equation 5a^2+a-2=0 are a=(-1+sqrt(41))/(10),a=(-1-sqrt(41))/(10)

Find the zeros of 5a^2+a-2=0

The zeros of 5a^2+a-2=0 are a=(-1+sqrt(41))/(10),a=(-1-sqrt(41))/(10)

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5 a^{2} + a - 2 = 0

a = \frac{- 1 + 41}{10}, a = \frac{- 1 - 41}{10}

Decimal Notation

a = 0.54031 \dots, a = - 0.74031 \dots

Solution steps

5 a^{2} + a - 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 2) = 41

a_{1, 2} = \frac{- 1 \pm 41}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- 1 + 41}{2 \cdot 5}, a_{2} = \frac{- 1 - 41}{2 \cdot 5}

a = \frac{- 1 + 41}{2 \cdot 5} : \frac{- 1 + 41}{10}

a = \frac{- 1 - 41}{2 \cdot 5} : \frac{- 1 - 41}{10}

The solutions to the quadratic equation are:

a = \frac{- 1 + 41}{10}, a = \frac{- 1 - 41}{10}

(k - 4)^{2} = 169

x^{2} + 14 x = 32

(2 x + 5)^{2} - (2 x + 5) - 6 = 0

28.1 8^{2} = w^{2} + (4 w)^{2}

z^{2} = - 16

What are the solutions to the equation 5a^2+a-2=0 ?
The solutions to the equation 5a^2+a-2=0 are a=(-1+sqrt(41))/(10),a=(-1-sqrt(41))/(10)
Find the zeros of 5a^2+a-2=0
The zeros of 5a^2+a-2=0 are a=(-1+sqrt(41))/(10),a=(-1-sqrt(41))/(10)