What are the solutions to the equation (x+2)(3x)=(x+2)(6) ?

The solutions to the equation (x+2)(3x)=(x+2)(6) are x=-2,x=2

Find the zeros of (x+2)(3x)=(x+2)(6)

The zeros of (x+2)(3x)=(x+2)(6) are x=-2,x=2

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(x + 2) (3 x) = (x + 2) (6)

x = - 2, x = 2

Solution steps

(x + 2) (3 x) = (x + 2) (6)

Move

(x + 2) (6)

to the left side

(x + 2) \cdot 3 x - (x + 2) \cdot 6 = 0

Factor

(x + 2) \cdot 3 x - (x + 2) \cdot 6 : 3 (x + 2) (x - 2)

3 (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x - 2 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions to the quadratic equation are:

x = - 2, x = 2

2 x^{2} + x = x^{2} + 20

(x - 4)^{2} = - 2

(2 y - 5)^{2} = 0

x, f (x + 4) = x^{2} - 2 x + 7

6 x (x - 1) = 40 - 5 x

What are the solutions to the equation (x+2)(3x)=(x+2)(6) ?
The solutions to the equation (x+2)(3x)=(x+2)(6) are x=-2,x=2
Find the zeros of (x+2)(3x)=(x+2)(6)
The zeros of (x+2)(3x)=(x+2)(6) are x=-2,x=2