What are the solutions to the equation (x-4)^2=-2 ?

The solutions to the equation (x-4)^2=-2 are x=sqrt(2)i+4,x=-sqrt(2)i+4

Find the zeros of (x-4)^2=-2

The zeros of (x-4)^2=-2 are x=sqrt(2)i+4,x=-sqrt(2)i+4

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(x - 4)^{2} = - 2

x = 2 i + 4, x = - 2 i + 4

Solution steps

(x - 4)^{2} = - 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = - 2 : x = 2 i + 4

Solve

x - 4 = - - 2 : x = - 2 i + 4

The solutions to the quadratic equation are:

x = 2 i + 4, x = - 2 i + 4

(2 y - 5)^{2} = 0

x, f (x + 4) = x^{2} - 2 x + 7

6 x (x - 1) = 40 - 5 x

x^{2} + (m - 3) x + m + 1 = 0

- 5 b^{2} + 9 b + 13 = - 6 b^{2}

What are the solutions to the equation (x-4)^2=-2 ?
The solutions to the equation (x-4)^2=-2 are x=sqrt(2)i+4,x=-sqrt(2)i+4
Find the zeros of (x-4)^2=-2
The zeros of (x-4)^2=-2 are x=sqrt(2)i+4,x=-sqrt(2)i+4