What are the solutions to the equation -5b^2+9b+13=-6b^2 ?

The solutions to the equation -5b^2+9b+13=-6b^2 are b=(-9+sqrt(29))/2 ,b=(-9-sqrt(29))/2

Find the zeros of -5b^2+9b+13=-6b^2

The zeros of -5b^2+9b+13=-6b^2 are b=(-9+sqrt(29))/2 ,b=(-9-sqrt(29))/2

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- 5 b^{2} + 9 b + 13 = - 6 b^{2}

b = \frac{- 9 + 29}{2}, b = \frac{- 9 - 29}{2}

Decimal Notation

b = - 1.80741 \dots, b = - 7.19258 \dots

Solution steps

- 5 b^{2} + 9 b + 13 = - 6 b^{2}

Move

6 b^{2}

to the left side

b^{2} + 9 b + 13 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 13 = 29

b_{1, 2} = \frac{- 9 \pm 29}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- 9 + 29}{2 \cdot 1}, b_{2} = \frac{- 9 - 29}{2 \cdot 1}

b = \frac{- 9 + 29}{2 \cdot 1} : \frac{- 9 + 29}{2}

b = \frac{- 9 - 29}{2 \cdot 1} : \frac{- 9 - 29}{2}

The solutions to the quadratic equation are:

b = \frac{- 9 + 29}{2}, b = \frac{- 9 - 29}{2}

- x^{2} + 5 x + 4 = 6

- 8 + 13 x^{2} = 0

50 x^{2} = 70

(x - 3) \cdot (x + 2) = 0

7 x^{2} - 3 x + 6 = 0

What are the solutions to the equation -5b^2+9b+13=-6b^2 ?
The solutions to the equation -5b^2+9b+13=-6b^2 are b=(-9+sqrt(29))/2 ,b=(-9-sqrt(29))/2
Find the zeros of -5b^2+9b+13=-6b^2
The zeros of -5b^2+9b+13=-6b^2 are b=(-9+sqrt(29))/2 ,b=(-9-sqrt(29))/2