What are the solutions to the equation -x^2+5x+4=6 ?

The solutions to the equation -x^2+5x+4=6 are x=(5-sqrt(17))/2 ,x=(5+sqrt(17))/2

Find the zeros of -x^2+5x+4=6

The zeros of -x^2+5x+4=6 are x=(5-sqrt(17))/2 ,x=(5+sqrt(17))/2

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- x^{2} + 5 x + 4 = 6

x = \frac{5 - 17}{2}, x = \frac{5 + 17}{2}

Decimal Notation

x = 0.43844 \dots, x = 4.56155 \dots

Solution steps

- x^{2} + 5 x + 4 = 6

Move

6

to the left side

- x^{2} + 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) ( - 2 )}{2 ( - 1 )}

5^{2} - 4 (- 1) (- 2) = 17

x_{1, 2} = \frac{- 5 \pm 17}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 17}{2 ( - 1 )}, x_{2} = \frac{- 5 - 17}{2 ( - 1 )}

x = \frac{- 5 + 17}{2 ( - 1 )} : \frac{5 - 17}{2}

x = \frac{- 5 - 17}{2 ( - 1 )} : \frac{5 + 17}{2}

The solutions to the quadratic equation are:

x = \frac{5 - 17}{2}, x = \frac{5 + 17}{2}

- 8 + 13 x^{2} = 0

50 x^{2} = 70

(x - 3) \cdot (x + 2) = 0

7 x^{2} - 3 x + 6 = 0

17 y + 5 y^{2} = 40

What are the solutions to the equation -x^2+5x+4=6 ?
The solutions to the equation -x^2+5x+4=6 are x=(5-sqrt(17))/2 ,x=(5+sqrt(17))/2
Find the zeros of -x^2+5x+4=6
The zeros of -x^2+5x+4=6 are x=(5-sqrt(17))/2 ,x=(5+sqrt(17))/2