What are the solutions to the equation 17y+5y^2=40 ?

The solutions to the equation 17y+5y^2=40 are y= 8/5 ,y=-5

Find the zeros of 17y+5y^2=40

The zeros of 17y+5y^2=40 are y= 8/5 ,y=-5

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17 y + 5 y^{2} = 40

y = \frac{8}{5}, y = - 5

Decimal Notation

y = 1.6, y = - 5

Solution steps

17 y + 5 y^{2} = 40

Move

40

to the left side

17 y + 5 y^{2} - 40 = 0

Write in the standard form

a x^{2} + b x + c = 0

5 y^{2} + 17 y - 40 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 5 ( - 40 )}{2 \cdot 5}

1 7^{2} - 4 \cdot 5 (- 40) = 33

y_{1, 2} = \frac{- 17 \pm 33}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- 17 + 33}{2 \cdot 5}, y_{2} = \frac{- 17 - 33}{2 \cdot 5}

y = \frac{- 17 + 33}{2 \cdot 5} : \frac{8}{5}

y = \frac{- 17 - 33}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

y = \frac{8}{5}, y = - 5

- 3 x^{2} + 20 x + 32 = 0

- 5 x^{2} + 180 = 0

20000 = x^{2} + 100 x

x, 0 = 3 x^{2} + 3 y^{2}

5 x^{2} - 1 = 4

What are the solutions to the equation 17y+5y^2=40 ?
The solutions to the equation 17y+5y^2=40 are y= 8/5 ,y=-5
Find the zeros of 17y+5y^2=40
The zeros of 17y+5y^2=40 are y= 8/5 ,y=-5