What are the solutions to the equation 5/2 x^2-4x+2=0 ?

The solutions to the equation 5/2 x^2-4x+2=0 are x= 4/5+i 2/5 ,x= 4/5-i 2/5

Find the zeros of 5/2 x^2-4x+2=0

The zeros of 5/2 x^2-4x+2=0 are x= 4/5+i 2/5 ,x= 4/5-i 2/5

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\frac{5}{2} x^{2} - 4 x + 2 = 0

x = \frac{4}{5} + i \frac{2}{5}, x = \frac{4}{5} - i \frac{2}{5}

Solution steps

\frac{5}{2} x^{2} - 4 x + 2 = 0

Multiply both sides by

2

5 x^{2} - 8 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

Simplify

(- 8)^{2} - 4 \cdot 5 \cdot 4 : 4 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 i}{2 \cdot 5}, x_{2} = \frac{- ( - 8 ) - 4 i}{2 \cdot 5}

x = \frac{- ( - 8 ) + 4 i}{2 \cdot 5} : \frac{4}{5} + i \frac{2}{5}

x = \frac{- ( - 8 ) - 4 i}{2 \cdot 5} : \frac{4}{5} - i \frac{2}{5}

The solutions to the quadratic equation are:

x = \frac{4}{5} + i \frac{2}{5}, x = \frac{4}{5} - i \frac{2}{5}

x^{2} + 175 = 0

x^{2} + 15 x - 8 = 0

2 x (x - 5) + 2 = 3 x

5 x - 7 x^{2} = 7

35 x^{2} - 2 = 7 - 14 x^{2}

What are the solutions to the equation 5/2 x^2-4x+2=0 ?
The solutions to the equation 5/2 x^2-4x+2=0 are x= 4/5+i 2/5 ,x= 4/5-i 2/5
Find the zeros of 5/2 x^2-4x+2=0
The zeros of 5/2 x^2-4x+2=0 are x= 4/5+i 2/5 ,x= 4/5-i 2/5