What are the solutions to the equation x(x+4)=-5 ?

The solutions to the equation x(x+4)=-5 are x=-2+i,x=-2-i

Find the zeros of x(x+4)=-5

The zeros of x(x+4)=-5 are x=-2+i,x=-2-i

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x (x + 4) = - 5

x = - 2 + i, x = - 2 - i

Solution steps

x (x + 4) = - 5

Expand

x (x + 4) : x^{2} + 4 x

x^{2} + 4 x = - 5

Move

5

to the left side

x^{2} + 4 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 5 : 2 i

x_{1, 2} = \frac{- 4 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 i}{2 \cdot 1}

x = \frac{- 4 + 2 i}{2 \cdot 1} : - 2 + i

x = \frac{- 4 - 2 i}{2 \cdot 1} : - 2 - i

The solutions to the quadratic equation are:

x = - 2 + i, x = - 2 - i

5 x^{2} + 3 x + 10 = 0

5 x^{2} + 12 x - 20 = - 3 x

x, x - y = x^{2} - y^{2}

2 x^{2} + 22 x = - 60

2 x^{2} - 5 x + 3 = 0

What are the solutions to the equation x(x+4)=-5 ?
The solutions to the equation x(x+4)=-5 are x=-2+i,x=-2-i
Find the zeros of x(x+4)=-5
The zeros of x(x+4)=-5 are x=-2+i,x=-2-i