What are the solutions to the equation factor 2x^2-5x+3=0 ?

The solutions to the equation factor 2x^2-5x+3=0 are x=1,x= 3/2

Find the zeros of factor 2x^2-5x+3=0

The zeros of factor 2x^2-5x+3=0 are x=1,x= 3/2

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2 x^{2} - 5 x + 3 = 0

x = 1, x = \frac{3}{2}

Decimal Notation

x = 1, x = 1.5

Solution steps

2 x^{2} - 5 x + 3 = 0

Factor

2 x^{2} - 5 x + 3 : (x - 1) (2 x - 3)

(x - 1) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x - 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions to the quadratic equation are:

x = 1, x = \frac{3}{2}

s^{2} = 81

2 x^{2} + 9 x + 8 = 0

27 x^{2} + 3 = 18 x

3 x^{2} + 5 x - 8 = 0

4 a^{2} - 11 a + 4 = 0

What are the solutions to the equation factor 2x^2-5x+3=0 ?
The solutions to the equation factor 2x^2-5x+3=0 are x=1,x= 3/2
Find the zeros of factor 2x^2-5x+3=0
The zeros of factor 2x^2-5x+3=0 are x=1,x= 3/2