What are the solutions to the equation 5x^2=17 ?

The solutions to the equation 5x^2=17 are x=sqrt(17/5),x=-sqrt(17/5)

Find the zeros of 5x^2=17

The zeros of 5x^2=17 are x=sqrt(17/5),x=-sqrt(17/5)

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5 x^{2} = 17

x = \frac{17}{5}, x = - \frac{17}{5}

Decimal Notation

x = 1.84390 \dots, x = - 1.84390 \dots

Solution steps

5 x^{2} = 17

Divide both sides by

5

x^{2} = \frac{17}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{17}{5}, x = - \frac{17}{5}

- 4 x^{2} + x - 25 = - 3 x^{2} + 17 x + 38

(3 y - 1) (y + 2) = 0

(x + 7)^{2} + 7 (x + 7) + 12 = 0

(4 x + 4) (a x - 1) - x^{2} + 4 = b x

x, x^{2} y^{2} + 3 x y = 1

What are the solutions to the equation 5x^2=17 ?
The solutions to the equation 5x^2=17 are x=sqrt(17/5),x=-sqrt(17/5)
Find the zeros of 5x^2=17
The zeros of 5x^2=17 are x=sqrt(17/5),x=-sqrt(17/5)