What are the solutions to the equation (x+7)^2+7(x+7)+12=0 ?

The solutions to the equation (x+7)^2+7(x+7)+12=0 are x=-10,x=-11

Find the zeros of (x+7)^2+7(x+7)+12=0

The zeros of (x+7)^2+7(x+7)+12=0 are x=-10,x=-11

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(x + 7)^{2} + 7 (x + 7) + 12 = 0

x = - 10, x = - 11

Solution steps

(x + 7)^{2} + 7 (x + 7) + 12 = 0

Expand

(x + 7)^{2} + 7 (x + 7) + 12 : x^{2} + 21 x + 110

x^{2} + 21 x + 110 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 1 \cdot 110}{2 \cdot 1}

2 1^{2} - 4 \cdot 1 \cdot 110 = 1

x_{1, 2} = \frac{- 21 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 21 + 1}{2 \cdot 1}, x_{2} = \frac{- 21 - 1}{2 \cdot 1}

x = \frac{- 21 + 1}{2 \cdot 1} : - 10

x = \frac{- 21 - 1}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

x = - 10, x = - 11

(4 x + 4) (a x - 1) - x^{2} + 4 = b x

x, x^{2} y^{2} + 3 x y = 1

x^{2} + \frac{3}{2} x = 0

(5 x + 2)^{2} = 32

1.3 x + 8.8 + (- 8) x^{2} = 0

What are the solutions to the equation (x+7)^2+7(x+7)+12=0 ?
The solutions to the equation (x+7)^2+7(x+7)+12=0 are x=-10,x=-11
Find the zeros of (x+7)^2+7(x+7)+12=0
The zeros of (x+7)^2+7(x+7)+12=0 are x=-10,x=-11