What are the solutions to the equation (5x+2)^2=32 ?

The solutions to the equation (5x+2)^2=32 are x=(4sqrt(2)-2)/5 ,x=(-4sqrt(2)-2)/5

Find the zeros of (5x+2)^2=32

The zeros of (5x+2)^2=32 are x=(4sqrt(2)-2)/5 ,x=(-4sqrt(2)-2)/5

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(5 x + 2)^{2} = 32

x = \frac{4 2 - 2}{5}, x = \frac{- 4 2 - 2}{5}

Decimal Notation

x = 0.73137 \dots, x = - 1.53137 \dots

Solution steps

(5 x + 2)^{2} = 32

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 2 = 32 : x = \frac{4 2 - 2}{5}

Solve

5 x + 2 = - 32 : x = \frac{- 4 2 - 2}{5}

The solutions to the quadratic equation are:

x = \frac{4 2 - 2}{5}, x = \frac{- 4 2 - 2}{5}

1.3 x + 8.8 + (- 8) x^{2} = 0

x^{2} + 2 x - 1 = 0

- 4 x^{2} + 12 x - 11 = 0

40 (p^{2} - 1) = 39 p

4 x^{2} - 23 x + 13 = - 3 x + 4

What are the solutions to the equation (5x+2)^2=32 ?
The solutions to the equation (5x+2)^2=32 are x=(4sqrt(2)-2)/5 ,x=(-4sqrt(2)-2)/5
Find the zeros of (5x+2)^2=32
The zeros of (5x+2)^2=32 are x=(4sqrt(2)-2)/5 ,x=(-4sqrt(2)-2)/5