What are the solutions to the equation -6x^2-24x+1=13 ?

The solutions to the equation -6x^2-24x+1=13 are x=-2-sqrt(2),x=-2+sqrt(2)

Find the zeros of -6x^2-24x+1=13

The zeros of -6x^2-24x+1=13 are x=-2-sqrt(2),x=-2+sqrt(2)

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- 6 x^{2} - 24 x + 1 = 13

x = - 2 - 2, x = - 2 + 2

Decimal Notation

x = - 3.41421 \dots, x = - 0.58578 \dots

Solution steps

- 6 x^{2} - 24 x + 1 = 13

Move

13

to the left side

- 6 x^{2} - 24 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 ( - 6 ) ( - 12 )}{2 ( - 6 )}

(- 24)^{2} - 4 (- 6) (- 12) = 122

x_{1, 2} = \frac{- ( - 24 ) \pm 12 2}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 12 2}{2 ( - 6 )}, x_{2} = \frac{- ( - 24 ) - 12 2}{2 ( - 6 )}

x = \frac{- ( - 24 ) + 12 2}{2 ( - 6 )} : - 2 - 2

x = \frac{- ( - 24 ) - 12 2}{2 ( - 6 )} : - 2 + 2

The solutions to the quadratic equation are:

x = - 2 - 2, x = - 2 + 2

- 3 x^{2} - 12 x + 9 = 0

2 x^{2} = 3 - 8 x

4 x^{2} - 13 x = 56

x, x^{2} + k x + x = 8 + k

(x - 5)^{2} - 3 = 0

What are the solutions to the equation -6x^2-24x+1=13 ?
The solutions to the equation -6x^2-24x+1=13 are x=-2-sqrt(2),x=-2+sqrt(2)
Find the zeros of -6x^2-24x+1=13
The zeros of -6x^2-24x+1=13 are x=-2-sqrt(2),x=-2+sqrt(2)