What are the solutions to the equation 5x^2+x-1/20 =0 ?

The solutions to the equation 5x^2+x-1/20 =0 are x=(-1+sqrt(2))/(10),x=-(1+sqrt(2))/(10)

Find the zeros of 5x^2+x-1/20 =0

The zeros of 5x^2+x-1/20 =0 are x=(-1+sqrt(2))/(10),x=-(1+sqrt(2))/(10)

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5 x^{2} + x - \frac{1}{20} = 0

x = \frac{- 1 + 2}{10}, x = - \frac{1 + 2}{10}

Decimal Notation

x = 0.04142 \dots, x = - 0.24142 \dots

Solution steps

5 x^{2} + x - \frac{1}{20} = 0

Multiply both sides by

20

100 x^{2} + 20 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 100 ( - 1 )}{2 \cdot 100}

2 0^{2} - 4 \cdot 100 (- 1) = 202

x_{1, 2} = \frac{- 20 \pm 20 2}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- 20 + 20 2}{2 \cdot 100}, x_{2} = \frac{- 20 - 20 2}{2 \cdot 100}

x = \frac{- 20 + 20 2}{2 \cdot 100} : \frac{- 1 + 2}{10}

x = \frac{- 20 - 20 2}{2 \cdot 100} : - \frac{1 + 2}{10}

The solutions to the quadratic equation are:

x = \frac{- 1 + 2}{10}, x = - \frac{1 + 2}{10}

2 (x^{2} - 6) = 5 x

(2 x + 9)^{2} - 25 = 0

- 3 t^{2} - t - 10 = - 4 t^{2}

- 4.9 x^{2} - 8 x + 30 = 0

2 x + 3 x^{2} = 0

What are the solutions to the equation 5x^2+x-1/20 =0 ?
The solutions to the equation 5x^2+x-1/20 =0 are x=(-1+sqrt(2))/(10),x=-(1+sqrt(2))/(10)
Find the zeros of 5x^2+x-1/20 =0
The zeros of 5x^2+x-1/20 =0 are x=(-1+sqrt(2))/(10),x=-(1+sqrt(2))/(10)