What are the solutions to the equation 7k^2-4=-39 ?

The solutions to the equation 7k^2-4=-39 are k=sqrt(5)i,k=-sqrt(5)i

Find the zeros of 7k^2-4=-39

The zeros of 7k^2-4=-39 are k=sqrt(5)i,k=-sqrt(5)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7 k^{2} - 4 = - 39

k = 5 i, k = - 5 i

Solution steps

7 k^{2} - 4 = - 39

Move

4

to the right side

7 k^{2} = - 35

Divide both sides by

7

k^{2} = - 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = - 5, k = - - 5

- 5 = 5 i

- - 5 = - 5 i

k = 5 i, k = - 5 i

\frac{( x + 5 ) ^{2}}{2} = 5

(r - 1)^{2} = - 5

12 x^{2} - 30 x + 18 = 0

2 x^{2} - 4 x + 3 = 0

x^{2} + 8 x = - 7

What are the solutions to the equation 7k^2-4=-39 ?
The solutions to the equation 7k^2-4=-39 are k=sqrt(5)i,k=-sqrt(5)i
Find the zeros of 7k^2-4=-39
The zeros of 7k^2-4=-39 are k=sqrt(5)i,k=-sqrt(5)i