What are the solutions to the equation 5x^2-32x-21=0 ?

The solutions to the equation 5x^2-32x-21=0 are x=7,x=-3/5

Find the zeros of 5x^2-32x-21=0

The zeros of 5x^2-32x-21=0 are x=7,x=-3/5

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5 x^{2} - 32 x - 21 = 0

x = 7, x = - \frac{3}{5}

Decimal Notation

x = 7, x = - 0.6

Solution steps

5 x^{2} - 32 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 \cdot 5 ( - 21 )}{2 \cdot 5}

(- 32)^{2} - 4 \cdot 5 (- 21) = 38

x_{1, 2} = \frac{- ( - 32 ) \pm 38}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 32 ) + 38}{2 \cdot 5}, x_{2} = \frac{- ( - 32 ) - 38}{2 \cdot 5}

x = \frac{- ( - 32 ) + 38}{2 \cdot 5} : 7

x = \frac{- ( - 32 ) - 38}{2 \cdot 5} : - \frac{3}{5}

The solutions to the quadratic equation are:

x = 7, x = - \frac{3}{5}

x^{2} - 2 x + 8 = 2

6 x^{2} - 3 = 8 x

30 x^{2} + 17 x + 2 = 0

15 (p^{2} - 1) = 16 p

2 x^{2} + 5 x + 2 = - 4

What are the solutions to the equation 5x^2-32x-21=0 ?
The solutions to the equation 5x^2-32x-21=0 are x=7,x=-3/5
Find the zeros of 5x^2-32x-21=0
The zeros of 5x^2-32x-21=0 are x=7,x=-3/5