What are the solutions to the equation 250=2x^2+(x^2)/2 ?

The solutions to the equation 250=2x^2+(x^2)/2 are x=10,x=-10

Find the zeros of 250=2x^2+(x^2)/2

The zeros of 250=2x^2+(x^2)/2 are x=10,x=-10

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250 = 2 x^{2} + \frac{x ^{2}}{2}

x = 10, x = - 10

Solution steps

250 = 2 x^{2} + \frac{x ^{2}}{2}

Switch sides

2 x^{2} + \frac{x ^{2}}{2} = 250

Multiply both sides by

2

4 x^{2} + x^{2} = 500

5 x^{2} = 500

Divide both sides by

5

x^{2} = 100

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 100, x = - 100

100 = 10

- 100 = - 10

x = 10, x = - 10

x, 3 x^{2} + x^{2} y = C

3 = (x - 1)^{2} + 3 (x + 2)

(7 + 2 x) (3 + 2 x) = 56

x^{2} - 5 x + 2 = - 4

6 x^{2} - 6 = 5 x

What are the solutions to the equation 250=2x^2+(x^2)/2 ?
The solutions to the equation 250=2x^2+(x^2)/2 are x=10,x=-10
Find the zeros of 250=2x^2+(x^2)/2
The zeros of 250=2x^2+(x^2)/2 are x=10,x=-10