What are the solutions to the equation (7+2x)(3+2x)=56 ?

The solutions to the equation (7+2x)(3+2x)=56 are x=(-5+2sqrt(15))/2 ,x=-(5+2sqrt(15))/2

Find the zeros of (7+2x)(3+2x)=56

The zeros of (7+2x)(3+2x)=56 are x=(-5+2sqrt(15))/2 ,x=-(5+2sqrt(15))/2

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(7 + 2 x) (3 + 2 x) = 56

x = \frac{- 5 + 2 15}{2}, x = - \frac{5 + 2 15}{2}

Decimal Notation

x = 1.37298 \dots, x = - 6.37298 \dots

Solution steps

(7 + 2 x) (3 + 2 x) = 56

Expand

(7 + 2 x) (3 + 2 x) : 21 + 20 x + 4 x^{2}

21 + 20 x + 4 x^{2} = 56

Move

56

to the left side

4 x^{2} + 20 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 ( - 35 )}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 (- 35) = 815

x_{1, 2} = \frac{- 20 \pm 8 15}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 20 + 8 15}{2 \cdot 4}, x_{2} = \frac{- 20 - 8 15}{2 \cdot 4}

x = \frac{- 20 + 8 15}{2 \cdot 4} : \frac{- 5 + 2 15}{2}

x = \frac{- 20 - 8 15}{2 \cdot 4} : - \frac{5 + 2 15}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 2 15}{2}, x = - \frac{5 + 2 15}{2}

x^{2} - 5 x + 2 = - 4

6 x^{2} - 6 = 5 x

5 x^{2} - 250 x + 3000 = 0

x, 2 x^{2} - 8 x + b y + 10 = 0

u^{2} - 7 u = - 10

What are the solutions to the equation (7+2x)(3+2x)=56 ?
The solutions to the equation (7+2x)(3+2x)=56 are x=(-5+2sqrt(15))/2 ,x=-(5+2sqrt(15))/2
Find the zeros of (7+2x)(3+2x)=56
The zeros of (7+2x)(3+2x)=56 are x=(-5+2sqrt(15))/2 ,x=-(5+2sqrt(15))/2