What are the solutions to the equation x(4x+6)=28 ?

The solutions to the equation x(4x+6)=28 are x=2,x=-7/2

Find the zeros of x(4x+6)=28

The zeros of x(4x+6)=28 are x=2,x=-7/2

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x (4 x + 6) = 28

x = 2, x = - \frac{7}{2}

Decimal Notation

x = 2, x = - 3.5

Solution steps

x (4 x + 6) = 28

Expand

x (4 x + 6) : 4 x^{2} + 6 x

4 x^{2} + 6 x = 28

Move

28

to the left side

4 x^{2} + 6 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 4 ( - 28 )}{2 \cdot 4}

6^{2} - 4 \cdot 4 (- 28) = 22

x_{1, 2} = \frac{- 6 \pm 22}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 6 + 22}{2 \cdot 4}, x_{2} = \frac{- 6 - 22}{2 \cdot 4}

x = \frac{- 6 + 22}{2 \cdot 4} : 2

x = \frac{- 6 - 22}{2 \cdot 4} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{7}{2}

t^{2} + 4 t = 0

0.3 x^{2} - 1.8 x - 0.3 = 0

(x - 5) (2 x) = (x - 5) (4)

x, x^{2} - x = 20

x^{2} + 40 x + 100 = 0

What are the solutions to the equation x(4x+6)=28 ?
The solutions to the equation x(4x+6)=28 are x=2,x=-7/2
Find the zeros of x(4x+6)=28
The zeros of x(4x+6)=28 are x=2,x=-7/2