What are the solutions to the equation -2x^2+20x=0 ?

The solutions to the equation -2x^2+20x=0 are x=0,x=10

Find the zeros of -2x^2+20x=0

The zeros of -2x^2+20x=0 are x=0,x=10

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- 2 x^{2} + 20 x = 0

x = 0, x = 10

Solution steps

- 2 x^{2} + 20 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

2 0^{2} - 4 (- 2) \cdot 0 = 20

x_{1, 2} = \frac{- 20 \pm 20}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 20 + 20}{2 ( - 2 )}, x_{2} = \frac{- 20 - 20}{2 ( - 2 )}

x = \frac{- 20 + 20}{2 ( - 2 )} : 0

x = \frac{- 20 - 20}{2 ( - 2 )} : 10

The solutions to the quadratic equation are:

x = 0, x = 10

x^{2} - 2 x - 5 = x + 5

x^{2} - 11 = 25

2 x + 8 = - x^{2}

(k - 7)^{2} = 289

- 4 x - 7 x^{2} + 15 = - 5 x^{2}

What are the solutions to the equation -2x^2+20x=0 ?
The solutions to the equation -2x^2+20x=0 are x=0,x=10
Find the zeros of -2x^2+20x=0
The zeros of -2x^2+20x=0 are x=0,x=10