What are the solutions to the equation 2t^2-8t=-3 ?

The solutions to the equation 2t^2-8t=-3 are t=(4+sqrt(10))/2 ,t=(4-sqrt(10))/2

Find the zeros of 2t^2-8t=-3

The zeros of 2t^2-8t=-3 are t=(4+sqrt(10))/2 ,t=(4-sqrt(10))/2

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2 t^{2} - 8 t = - 3

t = \frac{4 + 10}{2}, t = \frac{4 - 10}{2}

Decimal Notation

t = 3.58113 \dots, t = 0.41886 \dots

Solution steps

2 t^{2} - 8 t = - 3

Move

3

to the left side

2 t^{2} - 8 t + 3 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 8)^{2} - 4 \cdot 2 \cdot 3 = 210

t_{1, 2} = \frac{- ( - 8 ) \pm 2 10}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- ( - 8 ) + 2 10}{2 \cdot 2}, t_{2} = \frac{- ( - 8 ) - 2 10}{2 \cdot 2}

t = \frac{- ( - 8 ) + 2 10}{2 \cdot 2} : \frac{4 + 10}{2}

t = \frac{- ( - 8 ) - 2 10}{2 \cdot 2} : \frac{4 - 10}{2}

The solutions to the quadratic equation are:

t = \frac{4 + 10}{2}, t = \frac{4 - 10}{2}

3 x^{2} - 18 x + 1

5 w^{2} - 36 w = 32

2 x^{2} + 32 x + 244 = - 12

- x^{2} + 10 = 4 x + 2

(3 x - 9)^{2} = 5 x + 7

What are the solutions to the equation 2t^2-8t=-3 ?
The solutions to the equation 2t^2-8t=-3 are t=(4+sqrt(10))/2 ,t=(4-sqrt(10))/2
Find the zeros of 2t^2-8t=-3
The zeros of 2t^2-8t=-3 are t=(4+sqrt(10))/2 ,t=(4-sqrt(10))/2