What are the solutions to the equation 2x^2+32x+244=-12 ?

The solutions to the equation 2x^2+32x+244=-12 are x=-8+8i,x=-8-8i

Find the zeros of 2x^2+32x+244=-12

The zeros of 2x^2+32x+244=-12 are x=-8+8i,x=-8-8i

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2 x^{2} + 32 x + 244 = - 12

x = - 8 + 8 i, x = - 8 - 8 i

Solution steps

2 x^{2} + 32 x + 244 = - 12

Move

12

to the left side

2 x^{2} + 32 x + 256 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 2 \cdot 256}{2 \cdot 2}

Simplify

3 2^{2} - 4 \cdot 2 \cdot 256 : 32 i

x_{1, 2} = \frac{- 32 \pm 32 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 32 + 32 i}{2 \cdot 2}, x_{2} = \frac{- 32 - 32 i}{2 \cdot 2}

x = \frac{- 32 + 32 i}{2 \cdot 2} : - 8 + 8 i

x = \frac{- 32 - 32 i}{2 \cdot 2} : - 8 - 8 i

The solutions to the quadratic equation are:

x = - 8 + 8 i, x = - 8 - 8 i

- x^{2} + 10 = 4 x + 2

(3 x - 9)^{2} = 5 x + 7

c^{2} - 5 c + 9 = 0

y (y - 13) + 6 y = 18

7 (x + 5) (x - 3) - 5 (x + 3) (x - 3) = 0

What are the solutions to the equation 2x^2+32x+244=-12 ?
The solutions to the equation 2x^2+32x+244=-12 are x=-8+8i,x=-8-8i
Find the zeros of 2x^2+32x+244=-12
The zeros of 2x^2+32x+244=-12 are x=-8+8i,x=-8-8i