What are the solutions to the equation c^2-5c+9=0 ?

The solutions to the equation c^2-5c+9=0 are c= 5/2+i(sqrt(11))/2 ,c= 5/2-i(sqrt(11))/2

Find the zeros of c^2-5c+9=0

The zeros of c^2-5c+9=0 are c= 5/2+i(sqrt(11))/2 ,c= 5/2-i(sqrt(11))/2

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c^{2} - 5 c + 9 = 0

c = \frac{5}{2} + i \frac{11}{2}, c = \frac{5}{2} - i \frac{11}{2}

Solution steps

c^{2} - 5 c + 9 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

(- 5)^{2} - 4 \cdot 1 \cdot 9 : 11 i

c_{1, 2} = \frac{- ( - 5 ) \pm 11 i}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 5 ) + 11 i}{2 \cdot 1}, c_{2} = \frac{- ( - 5 ) - 11 i}{2 \cdot 1}

c = \frac{- ( - 5 ) + 11 i}{2 \cdot 1} : \frac{5}{2} + i \frac{11}{2}

c = \frac{- ( - 5 ) - 11 i}{2 \cdot 1} : \frac{5}{2} - i \frac{11}{2}

The solutions to the quadratic equation are:

c = \frac{5}{2} + i \frac{11}{2}, c = \frac{5}{2} - i \frac{11}{2}

y (y - 13) + 6 y = 18

7 (x + 5) (x - 3) - 5 (x + 3) (x - 3) = 0

2 x^{2} + 20 x + 15 = 127

6 x^{2} - 46 x + 312 = 14 x

\frac{n ( n - 3 )}{2} = 2 n

What are the solutions to the equation c^2-5c+9=0 ?
The solutions to the equation c^2-5c+9=0 are c= 5/2+i(sqrt(11))/2 ,c= 5/2-i(sqrt(11))/2
Find the zeros of c^2-5c+9=0
The zeros of c^2-5c+9=0 are c= 5/2+i(sqrt(11))/2 ,c= 5/2-i(sqrt(11))/2