What are the solutions to the equation x(x+2)=120 ?

The solutions to the equation x(x+2)=120 are x=10,x=-12

Find the zeros of x(x+2)=120

The zeros of x(x+2)=120 are x=10,x=-12

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x (x + 2) = 120

x = 10, x = - 12

Solution steps

x (x + 2) = 120

Expand

x (x + 2) : x^{2} + 2 x

x^{2} + 2 x = 120

Move

120

to the left side

x^{2} + 2 x - 120 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 120 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 120) = 22

x_{1, 2} = \frac{- 2 \pm 22}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 22}{2 \cdot 1}, x_{2} = \frac{- 2 - 22}{2 \cdot 1}

x = \frac{- 2 + 22}{2 \cdot 1} : 10

x = \frac{- 2 - 22}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 10, x = - 12

x, \frac{x ^{2}}{18} = r

s^{2} + 2 s + 20 = 0

y^{2} + 2 y + 5 y = 5 y^{2} - 4 y

x, 6 x^{2} - 6 x y + 6 x = 0

4 x^{2} - 36 x + 85 = 0

What are the solutions to the equation x(x+2)=120 ?
The solutions to the equation x(x+2)=120 are x=10,x=-12
Find the zeros of x(x+2)=120
The zeros of x(x+2)=120 are x=10,x=-12