What are the solutions to the equation factor 3y^2+2y-1=0 ?

The solutions to the equation factor 3y^2+2y-1=0 are y= 1/3 ,y=-1

Find the zeros of factor 3y^2+2y-1=0

The zeros of factor 3y^2+2y-1=0 are y= 1/3 ,y=-1

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3 y^{2} + 2 y - 1 = 0

y = \frac{1}{3}, y = - 1

Decimal Notation

y = 0.33333 \dots, y = - 1

Solution steps

3 y^{2} + 2 y - 1 = 0

Factor

3 y^{2} + 2 y - 1 : (3 y - 1) (y + 1)

(3 y - 1) (y + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 y - 1 = 0 or y + 1 = 0

Solve

3 y - 1 = 0 : y = \frac{1}{3}

Solve

y + 1 = 0 : y = - 1

The solutions to the quadratic equation are:

y = \frac{1}{3}, y = - 1

- 4 x^{2} - 16 x - 216 = 0

- 8 x^{2} - 24 x + 3 = 2

x^{2} - 12 x = 20

x^{2} + x - 6 = x + 3

92 = 20 + 26 t - 2 t^{2}

What are the solutions to the equation factor 3y^2+2y-1=0 ?
The solutions to the equation factor 3y^2+2y-1=0 are y= 1/3 ,y=-1
Find the zeros of factor 3y^2+2y-1=0
The zeros of factor 3y^2+2y-1=0 are y= 1/3 ,y=-1