What are the solutions to the equation 9=x^2+6x+7 ?

The solutions to the equation 9=x^2+6x+7 are x=-3+sqrt(11),x=-3-sqrt(11)

Find the zeros of 9=x^2+6x+7

The zeros of 9=x^2+6x+7 are x=-3+sqrt(11),x=-3-sqrt(11)

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9 = x^{2} + 6 x + 7

x = - 3 + 11, x = - 3 - 11

Decimal Notation

x = 0.31662 \dots, x = - 6.31662 \dots

Solution steps

9 = x^{2} + 6 x + 7

Switch sides

x^{2} + 6 x + 7 = 9

Move

9

to the left side

x^{2} + 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 2) = 211

x_{1, 2} = \frac{- 6 \pm 2 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 11}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 11}{2 \cdot 1}

x = \frac{- 6 + 2 11}{2 \cdot 1} : - 3 + 11

x = \frac{- 6 - 2 11}{2 \cdot 1} : - 3 - 11

The solutions to the quadratic equation are:

x = - 3 + 11, x = - 3 - 11

2 x^{2} - 3 x + 16 = 0

(x + 4) (x + 7) = 8

3 x^{2} - 6 x = 12 x

3 x^{2} - 3 = 6 x - 3

4 + 2 x - x^{2}

What are the solutions to the equation 9=x^2+6x+7 ?
The solutions to the equation 9=x^2+6x+7 are x=-3+sqrt(11),x=-3-sqrt(11)
Find the zeros of 9=x^2+6x+7
The zeros of 9=x^2+6x+7 are x=-3+sqrt(11),x=-3-sqrt(11)