What are the solutions to the equation x^2=-x^2+6 ?

The solutions to the equation x^2=-x^2+6 are x=sqrt(3),x=-sqrt(3)

Find the zeros of x^2=-x^2+6

The zeros of x^2=-x^2+6 are x=sqrt(3),x=-sqrt(3)

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x^{2} = - x^{2} + 6

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

x^{2} = - x^{2} + 6

Move

x^{2}

to the left side

2 x^{2} = 6

Divide both sides by

2

x^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3, x = - 3

y, x y^{2} - 9 x - y - 1 = 0

20 x^{2} - 9 x - 20 = 0

x^{2} - 4 x - 17 = 0

(2 x + 3)^{2} = 7

4 x (x + 5) = 0

What are the solutions to the equation x^2=-x^2+6 ?
The solutions to the equation x^2=-x^2+6 are x=sqrt(3),x=-sqrt(3)
Find the zeros of x^2=-x^2+6
The zeros of x^2=-x^2+6 are x=sqrt(3),x=-sqrt(3)