What are the solutions to the equation 20x^2-9x-20=0 ?

The solutions to the equation 20x^2-9x-20=0 are x= 5/4 ,x=-4/5

Find the zeros of 20x^2-9x-20=0

The zeros of 20x^2-9x-20=0 are x= 5/4 ,x=-4/5

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20 x^{2} - 9 x - 20 = 0

x = \frac{5}{4}, x = - \frac{4}{5}

Decimal Notation

x = 1.25, x = - 0.8

Solution steps

20 x^{2} - 9 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 20 ( - 20 )}{2 \cdot 20}

(- 9)^{2} - 4 \cdot 20 (- 20) = 41

x_{1, 2} = \frac{- ( - 9 ) \pm 41}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 41}{2 \cdot 20}, x_{2} = \frac{- ( - 9 ) - 41}{2 \cdot 20}

x = \frac{- ( - 9 ) + 41}{2 \cdot 20} : \frac{5}{4}

x = \frac{- ( - 9 ) - 41}{2 \cdot 20} : - \frac{4}{5}

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = - \frac{4}{5}

x^{2} - 4 x - 17 = 0

(2 x + 3)^{2} = 7

4 x (x + 5) = 0

x, 5 x^{2} + x y^{2} = c

36 d^{2} + 60 d + 25 = 16

What are the solutions to the equation 20x^2-9x-20=0 ?
The solutions to the equation 20x^2-9x-20=0 are x= 5/4 ,x=-4/5
Find the zeros of 20x^2-9x-20=0
The zeros of 20x^2-9x-20=0 are x= 5/4 ,x=-4/5