What are the solutions to the equation 36d^2+60d+25=16 ?

The solutions to the equation 36d^2+60d+25=16 are d=-1/6 ,d=-3/2

Find the zeros of 36d^2+60d+25=16

The zeros of 36d^2+60d+25=16 are d=-1/6 ,d=-3/2

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36 d^{2} + 60 d + 25 = 16

d = - \frac{1}{6}, d = - \frac{3}{2}

Decimal Notation

d = - 0.16666 \dots, d = - 1.5

Solution steps

36 d^{2} + 60 d + 25 = 16

Move

16

to the left side

36 d^{2} + 60 d + 9 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 \cdot 36 \cdot 9}{2 \cdot 36}

6 0^{2} - 4 \cdot 36 \cdot 9 = 48

d_{1, 2} = \frac{- 60 \pm 48}{2 \cdot 36}

Separate the solutions

d_{1} = \frac{- 60 + 48}{2 \cdot 36}, d_{2} = \frac{- 60 - 48}{2 \cdot 36}

d = \frac{- 60 + 48}{2 \cdot 36} : - \frac{1}{6}

d = \frac{- 60 - 48}{2 \cdot 36} : - \frac{3}{2}

The solutions to the quadratic equation are:

d = - \frac{1}{6}, d = - \frac{3}{2}

112 x^{2} - 56 x + 3 = 0

(k - 1) y^{2} - 5 y + 3 k - 7 = 0

x^{2} + 4 x - 45 = 0

- 2 x^{2} - 6 x + 7 = 0

2 u^{2} - 5 u - 3 = 0

What are the solutions to the equation 36d^2+60d+25=16 ?
The solutions to the equation 36d^2+60d+25=16 are d=-1/6 ,d=-3/2
Find the zeros of 36d^2+60d+25=16
The zeros of 36d^2+60d+25=16 are d=-1/6 ,d=-3/2