What are the solutions to the equation 2u^2-5u-3=0 ?

The solutions to the equation 2u^2-5u-3=0 are u=3,u=-1/2

Find the zeros of 2u^2-5u-3=0

The zeros of 2u^2-5u-3=0 are u=3,u=-1/2

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2 u^{2} - 5 u - 3 = 0

u = 3, u = - \frac{1}{2}

Decimal Notation

u = 3, u = - 0.5

Solution steps

2 u^{2} - 5 u - 3 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 3) = 7

u_{1, 2} = \frac{- ( - 5 ) \pm 7}{2 \cdot 2}

Separate the solutions

u_{1} = \frac{- ( - 5 ) + 7}{2 \cdot 2}, u_{2} = \frac{- ( - 5 ) - 7}{2 \cdot 2}

u = \frac{- ( - 5 ) + 7}{2 \cdot 2} : 3

u = \frac{- ( - 5 ) - 7}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

u = 3, u = - \frac{1}{2}

x, y = - 0.02 x^{2} + x + 2.6

4 x (x - 2) + 3 (x - 3) = - 3

x, y^{4} = (x + 2)^{2}

4 z^{2} - 19 z + 18 = 0

(x - 6) (x - 4) = - 1

What are the solutions to the equation 2u^2-5u-3=0 ?
The solutions to the equation 2u^2-5u-3=0 are u=3,u=-1/2
Find the zeros of 2u^2-5u-3=0
The zeros of 2u^2-5u-3=0 are u=3,u=-1/2