What are the solutions to the equation -2x^2-32x-112=0 ?

The solutions to the equation -2x^2-32x-112=0 are x=-2(4+sqrt(2)),x=-2(4-sqrt(2))

Find the zeros of -2x^2-32x-112=0

The zeros of -2x^2-32x-112=0 are x=-2(4+sqrt(2)),x=-2(4-sqrt(2))

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- 2 x^{2} - 32 x - 112 = 0

x = - 2 (4 + 2), x = - 2 (4 - 2)

Decimal Notation

x = - 10.82842 \dots, x = - 5.17157 \dots

Solution steps

- 2 x^{2} - 32 x - 112 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 ( - 2 ) ( - 112 )}{2 ( - 2 )}

(- 32)^{2} - 4 (- 2) (- 112) = 82

x_{1, 2} = \frac{- ( - 32 ) \pm 8 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 32 ) + 8 2}{2 ( - 2 )}, x_{2} = \frac{- ( - 32 ) - 8 2}{2 ( - 2 )}

x = \frac{- ( - 32 ) + 8 2}{2 ( - 2 )} : - 2 (4 + 2)

x = \frac{- ( - 32 ) - 8 2}{2 ( - 2 )} : - 2 (4 - 2)

The solutions to the quadratic equation are:

x = - 2 (4 + 2), x = - 2 (4 - 2)

3 x^{2} - 24 = - 9 x^{2}

5 x^{2} + 3 x - 14 = 0

(11 x - 1)^{2} - 4 (11 x - 1) - 5 = 0

0 = 2 x^{2} + 4 x - 5

24 = - 0.5 t^{2} + 3.2 t + 22

What are the solutions to the equation -2x^2-32x-112=0 ?
The solutions to the equation -2x^2-32x-112=0 are x=-2(4+sqrt(2)),x=-2(4-sqrt(2))
Find the zeros of -2x^2-32x-112=0
The zeros of -2x^2-32x-112=0 are x=-2(4+sqrt(2)),x=-2(4-sqrt(2))