What are the solutions to the equation 4x(2x-1)-x=3 ?

The solutions to the equation 4x(2x-1)-x=3 are x=1,x=-3/8

Find the zeros of 4x(2x-1)-x=3

The zeros of 4x(2x-1)-x=3 are x=1,x=-3/8

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4 x (2 x - 1) - x = 3

x = 1, x = - \frac{3}{8}

Decimal Notation

x = 1, x = - 0.375

Solution steps

4 x (2 x - 1) - x = 3

Expand

4 x (2 x - 1) - x : 8 x^{2} - 5 x

8 x^{2} - 5 x = 3

Move

3

to the left side

8 x^{2} - 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 8 ( - 3 )}{2 \cdot 8}

(- 5)^{2} - 4 \cdot 8 (- 3) = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 8}, x_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 8}

x = \frac{- ( - 5 ) + 11}{2 \cdot 8} : 1

x = \frac{- ( - 5 ) - 11}{2 \cdot 8} : - \frac{3}{8}

The solutions to the quadratic equation are:

x = 1, x = - \frac{3}{8}

2 x^{2} + 4 x - 1

x, v + w = x^{2} yz

(x - 1) (x + 1) = 1

9 x^{2} = 225

(x - 6)^{2} - 7 = 0

What are the solutions to the equation 4x(2x-1)-x=3 ?
The solutions to the equation 4x(2x-1)-x=3 are x=1,x=-3/8
Find the zeros of 4x(2x-1)-x=3
The zeros of 4x(2x-1)-x=3 are x=1,x=-3/8