What are the solutions to the equation (x-1)(x+1)=1 ?

The solutions to the equation (x-1)(x+1)=1 are x=sqrt(2),x=-sqrt(2)

Find the zeros of (x-1)(x+1)=1

The zeros of (x-1)(x+1)=1 are x=sqrt(2),x=-sqrt(2)

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(x - 1) (x + 1) = 1

x = 2, x = - 2

Decimal Notation

x = 1.41421 \dots, x = - 1.41421 \dots

Solution steps

(x - 1) (x + 1) = 1

Expand

(x - 1) (x + 1) : x^{2} - 1

x^{2} - 1 = 1

Move

1

to the left side

x^{2} - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 2) = 22

x_{1, 2} = \frac{- 0 \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 2 2}{2 \cdot 1}, x_{2} = \frac{- 0 - 2 2}{2 \cdot 1}

x = \frac{- 0 + 2 2}{2 \cdot 1} : 2

x = \frac{- 0 - 2 2}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 2, x = - 2

9 x^{2} = 225

(x - 6)^{2} - 7 = 0

x, x^{2} - k x + 24 = 0

\frac{25}{169} = b^{2}

0.1 x^{2} + 100 x + 8 = 1000

What are the solutions to the equation (x-1)(x+1)=1 ?
The solutions to the equation (x-1)(x+1)=1 are x=sqrt(2),x=-sqrt(2)
Find the zeros of (x-1)(x+1)=1
The zeros of (x-1)(x+1)=1 are x=sqrt(2),x=-sqrt(2)