What are the solutions to the equation 25/169 =b^2 ?

The solutions to the equation 25/169 =b^2 are b= 5/13 ,b=-5/13

Find the zeros of 25/169 =b^2

The zeros of 25/169 =b^2 are b= 5/13 ,b=-5/13

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\frac{25}{169} = b^{2}

b = \frac{5}{13}, b = - \frac{5}{13}

Decimal Notation

b = 0.38461 \dots, b = - 0.38461 \dots

Solution steps

\frac{25}{169} = b^{2}

Switch sides

b^{2} = \frac{25}{169}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = \frac{25}{169}, b = - \frac{25}{169}

\frac{25}{169} = \frac{5}{13}

- \frac{25}{169} = - \frac{5}{13}

b = \frac{5}{13}, b = - \frac{5}{13}

0.1 x^{2} + 100 x + 8 = 1000

(x + 9) (x + 4) = - 26

9 y^{2} - y + 8 = 0

5 u^{2} - 19 u - 4 = 0

- 5 x^{2} + 7 x - 1 = 0

What are the solutions to the equation 25/169 =b^2 ?
The solutions to the equation 25/169 =b^2 are b= 5/13 ,b=-5/13
Find the zeros of 25/169 =b^2
The zeros of 25/169 =b^2 are b= 5/13 ,b=-5/13