What are the solutions to the equation 9y^2-y+8=0 ?

The solutions to the equation 9y^2-y+8=0 are y= 1/18+i(sqrt(287))/(18),y= 1/18-i(sqrt(287))/(18)

Find the zeros of 9y^2-y+8=0

The zeros of 9y^2-y+8=0 are y= 1/18+i(sqrt(287))/(18),y= 1/18-i(sqrt(287))/(18)

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9 y^{2} - y + 8 = 0

y = \frac{1}{18} + i \frac{287}{18}, y = \frac{1}{18} - i \frac{287}{18}

Solution steps

9 y^{2} - y + 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 9 \cdot 8}{2 \cdot 9}

Simplify

(- 1)^{2} - 4 \cdot 9 \cdot 8 : 287 i

y_{1, 2} = \frac{- ( - 1 ) \pm 287 i}{2 \cdot 9}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 287 i}{2 \cdot 9}, y_{2} = \frac{- ( - 1 ) - 287 i}{2 \cdot 9}

y = \frac{- ( - 1 ) + 287 i}{2 \cdot 9} : \frac{1}{18} + i \frac{287}{18}

y = \frac{- ( - 1 ) - 287 i}{2 \cdot 9} : \frac{1}{18} - i \frac{287}{18}

The solutions to the quadratic equation are:

y = \frac{1}{18} + i \frac{287}{18}, y = \frac{1}{18} - i \frac{287}{18}

5 u^{2} - 19 u - 4 = 0

- 5 x^{2} + 7 x - 1 = 0

- x^{2} + 12 x - 6 = 0

x^{2} - 54 = - 5 x^{2}

5 x^{2} - 12 = 113

What are the solutions to the equation 9y^2-y+8=0 ?
The solutions to the equation 9y^2-y+8=0 are y= 1/18+i(sqrt(287))/(18),y= 1/18-i(sqrt(287))/(18)
Find the zeros of 9y^2-y+8=0
The zeros of 9y^2-y+8=0 are y= 1/18+i(sqrt(287))/(18),y= 1/18-i(sqrt(287))/(18)